How to implement Gaussian Approximation
3 views (last 30 days)
Show older comments
I'm having some trouble trying to implement the following function:

To express the inverse function of rho I have used a numerical approximation for the second equality of the piecewise defined function, as it does not have an analytical solution.
I have the impression that something must have been done wrongly, as the result should be more 'positive' (greater than 0) for each iteration.
I will leave here my code:
l = [0 0.3078 0.27287 0 0 0 0.41933];
r = [0 0 0 0 0 0.4 0.6];
sigma = 0.8747;
mu0 = 2/sigma;
iterations = 50;
% Density evolution algorithm depiction for finding the treshold of irregular LDPC codes
syms x;
l_idle = zeros(1,length(l));
r_idle = zeros(1,length(r));
Q_1 = exp(-0.4527*x^0.86 + 0.0218);
Q_2 = sqrt(pi/x)*exp(-x/4)*(1-20/(7*x));
mu = zeros(1,iterations+1);
for k=2:1:iterations+1
for i = 1:length(l_idle)
if ((mu0 + (i-1)*mu(k-1)) < 10)
l_idle(i) = subs(Q_1,x,(mu0 + (i-1)*mu(k-1)));
else
l_idle(i) = subs(Q_2,x,(mu0 + (i-1)*mu(k-1)));
end
end
lambda = l*transpose(l_idle);
for j = 1:length(r_idle)
b = 1-(1-lambda)^(j-1);
g = subs(Q_1,x,b);
if or(subs(Q_1,x,10) < g, subs(Q_1,x,0) >= g)
r_idle(j) = (1/0.4527*(0.0218-log(g)))^(1/0.86);
else
xx = linspace(0, subs(Q_2,x,10), 10000);
yy = f(xx);
r_idle(j) = interp1(yy,xx,b);
end
end
mu(k) = r*transpose(r_idle);
end
If anyone has any question, I will be pleased to answer you.
Thank you in advance, and may you have a nice week!
0 Comments
Answers (0)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!