Minimum value in 2d matrix but with restriction

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I have a n*m matrix. for example A = [16 2 0 13; 5 11 10 8; 0 7 6 1; 16 14 15 0]. I want to find the min value>0 (i.e.,min value should not be 0, it can be any other value) in the matrix and also i need to find the index of matrix. I tried using [c,i] = min (A(A~=0)) and the answer I obtained is c = 1 (the min value as 1) and i = 13 (the index as 13). then when I used [d,e] = ind2sub(size(A),i) it gave me the answer as 1 and 4 i.e., index as (1,4) which is wrong. actually the index should be (3,4) because the index of 1 in matrix A is (3,4). Please help me in finding the correct index of the min value 1.

Accepted Answer

Thomas
Thomas on 29 Mar 2012

More Answers (1)

Sean de Wolski
Sean de Wolski on 29 Mar 2012
x2 = x;
x2(~x) = inf;
[val idx] = min(x2)

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