I dont understand this code with dir and sprintf
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Zahra S. Abd Al-Hassan
on 2 May 2017
Commented: Stephen23
on 3 May 2017
Hey
I want to convert mat-files and my supervisor gave me this matlab-code to do it with. I am not sure I understand it fully, can you help?

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Accepted Answer
Walter Roberson
on 2 May 2017
Edited: Stephen23
on 3 May 2017
1) Do not use "path" as a variable name, as doing that interferes with using the MATLAB path.
2) Instead of
files = dir(sprintf('%s/%s/*.mat', path, hemi(ee))
use
files = dir( fullfile(path, hemi(ee), '*.mat') )
and later when the file name is being constructed, use fullfile() then as well.
3)
sprintf([''], ii, segment)
is going to result in the empty vector because of the empty format '' . The purpose of that code is confusing.
4) it really looks to me as if the code for filesB and B is wrong. Different directories are being referred to in the different lines.
2 Comments
Walter Roberson
on 3 May 2017
%s means that a string should be read from the next available parameter and transfered to the output as characters.
segment = 'name'
means that at some point in the development of the program, there was a directory that was named either literally 'name' or else name with a numeric prefix, such as '1name', '2name' and so on. But with the [''] format of the sprintf() the content of the segment variable is being ignored.
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