why the conv(u,v,'same') choose the a vector a little right deviated to center position
1 view (last 30 days)
Show older comments
Tsung-Ju Yang
on 30 Mar 2017
Commented: Tsung-Ju Yang
on 31 Mar 2017
For example
>> a=[1:10];
>> b=[7:7:28];
>> conv(a,b)
ans =
7 28 70 140 210 280 350 420 490 560 553 462 280
>>conv(a,b,'same')
ans =
70 140 210 280 350 420 490 560 553 462
The same option give a vector vector from element 70. Why not from element 28? Are there any math/enginerr reasons?
0 Comments
Accepted Answer
Greg Dionne
on 30 Mar 2017
If b is of odd length, you will obtain what you expect.
For even length it will move to the next available point having the gap at the beginning, not at the end. To get the other way, try:
>> fliplr(conv(fliplr(a),fliplr(b),'same'))
ans =
28 70 140 210 280 350 420 490 560 553
3 Comments
Image Analyst
on 30 Mar 2017
Basically it's shifted a half element to the side if you're using an even number of elements in your scanning kernel window instead of an odd number.
More Answers (0)
See Also
Categories
Find more on Spectral Estimation in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!