points lying inside a polygon and a circle
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How can I find the number of point lies inside both a circle and a polygon (the point should lie in the mutual/overlapping area in between the circle and the polygon) ?
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More Answers (1)
Image Analyst
on 30 Jan 2017
Did you try
count = 0;
if inpolygon(x,y,xCircle,yCircle) && inpolygon(x,y,xPoly,yPoly)
count = count + 1
end
where you call inpolygon twice, once passing in the circle coordinates and once passing in the polygon coordinates and then ANDing the two results together?
6 Comments
KalMandy
on 30 Jan 2017
Image Analyst
on 30 Jan 2017
Edited: Image Analyst
on 30 Jan 2017
Yes, if you have the coordinates for the perimeter of the circle. If you don't, then see Matt J's formula below. You didn't specify in what form you have information about the circle. You'd put my code in a loop over all (x,y) points that you have.
count = 0;
for k = 1 : length(x)
if inpolygon(x(k),y(k),xCircle,yCircle) && inpolygon(x(k),y(k),xPoly,yPoly)
count = count + 1
end
end
Same for Matt's code - loop over all x,y that you have.
Matt J
on 30 Jan 2017
Same for Matt's code - loop over all x,y that you have.
Neither approach requires a loop over x,y. INPOLYGON is vectorized.
Image Analyst
on 30 Jan 2017
You're right. x and y can be a vector of coordinates. Here's a demo:
% Make circle.
x0 = 20;
y0 = 30;
R = 15;
% Plot circle
pos = [x0-R, y0-R, 2*R, 2*R];
rectangle('Position', pos, 'Curvature',[1 1]);
hold on;
% Make polygon
xv = [10, 30, 30, 10, 10];
yv = [40, 40, 5, 5, 40];
plot(xv, yv, 'b-');
grid on;
% Make 60 points for x and y
numPoints = 60;
x = 70 * rand(1, numPoints);
y = 70 * rand(1, numPoints);
plot(x, y, 'r*');
% Now count how many are in both the circle and the polygon.
count = sum(inpolygon(x,y,xv,yv) & ((x-x0).^2+(y-y0).^2<=R^2))
KalMandy
on 30 Jan 2017
hanif hamden
on 25 Apr 2019
If i put (x,y) in geographical coordinate and I want my radius is 10km. How should I do that?
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