warning in solving MeijerG function on Matlab?

I'm trying to plot an equation contains meijerG function, i have an m.file for the meijerG function, when i run the code, i get a warning, it may be the reason why my plot has few errors, but i do not inderstand the warning, so anyone can just help me to know what is the warning wbout to fix it?

Here is the code:

    a=0;

   k_0=.1;

    step = 0.1; range = 0:step:3;
  variance1_0db = sqrt(1/(2.*(k_0+1)));
     variance2_0db = sqrt(2/(2.*(k_0+1)));

   mean1_0db=sqrt(k_0/(k_0+1)); % mean of underlying Gaussian random variables
  mean2_0db=sqrt((2.*k_0)/(k_0+1)); 

    parfor m=0:30
   for n=0:30
    c2=(1./(2.*variance1_0db.^2.*variance2_0db.^2)).*exp(-mean1_0db.^2/(2.*variance1_0db.^2)).*exp(-mean2_0db.^2./(2.*variance2_0db.^2)).*(1./((factorial(m).^2).*(factorial(n)).^2))*   (((mean1_0db)./(2.*variance1_0db.^2)).^(2.*m)).*(((mean2_0db)./(2.*variance2_0db.^2)).^(2.*n))*((1./(2.*(variance2_0db.^2))).^(m-n));
   f=(c2).*(range.^(2.*m+1)).*MeijerG({[1+m-n,1], []}, {[], []}, ((4.*variance1_0db.^2.*variance2_0db.^2)./(range.^2)));
    a=a+f;
   end
   end
   plot(range, a,'b');

and the m.file for the MeijerG is attached.

And here is the warning: > In MeijerG at 91 In parallel_function>make_general_channel/channel_general at 923 In remoteParallelFunction at 38

Answer 1

[Walter Roberson]

Your range variable starts at 0. You have a division by range. That gets you infinity at that location. You then try to calculate MeijerG at infinity; that returns back a symbolic placeholder that cannot be evaluated to a numeric value, which leads to the warning.

Solution: do not use 0 in range.

[Deema42]

great! Thank you.