how to fix error in selecting minimum value from iteration matrix?
1 view (last 30 days)
Show older comments
I'm running this code. I want to have all iterations saved in Total_all matrix and from that matrix select the minimum value. then display the corresponding matrices in result which show minimum value. the code is below.but the code is giving minValue as a complete row. can any one please check this?
tic;
no_of_machines=7;
no_of_cells=3;
No_of_Parts = 6;
P1=[1 0 0 1 0 1 1;1 1 0 0 1 0 1];
P2=[0 1 1 1 0 0 1;1 0 1 0 1 1 0];
P3=[1 0 0 1 1 0 0;0 1 1 0 0 0 1];
P4=[1 0 0 0 1 0 1;0 1 0 1 0 1 0];
P5=[1 1 0 0 0 1 0;1 1 0 0 1 0 1];
P6=[0 1 0 0 0 1 1;1 1 0 1 0 1 0];
P = [P1;P2;P3;P4;P5;P6];
z = [size(P1,1) size(P2,1) size(P3,1) size(P4,1) size(P5,1) size(P6,1)];
c = [0 cumsum(z(1:end-1))];
a = allcomb(1:z(1),1:z(2),1:z(3),1:z(4),1:z(5),1:z(6));
n = size(a,1);
all_comb_of_routes = cell(1,n);
for k=1:n
all_comb_of_routes{k} = P(c+a(k,:),:);
end
CELL = zeros(no_of_cells^no_of_machines,no_of_machines);
t = 0;
for k = 0:(no_of_cells^no_of_machines)-1 %k=(2187-1=2186)
s = dec2base(k,no_of_cells,no_of_machines);
if length(unique(s))==no_of_cells
t = t+1;
CELL(t,:) = s-'0'+1;
end
end
CELL = CELL(1:t,:);
combination_array=num2cell(CELL,2);% all possible combinations
[r1,c1]=size(combination_array);
for l=1:r1
R=1:numel(combination_array{l});
Z = zeros(R(end),max(combination_array{l}));
Z(sub2ind(size(Z),R,combination_array{l})) = 1;
allCells_array{l}=Z; % machine cell matrix array of all combinations
end
[r2,c2]=size(all_comb_of_routes);
total_all= zeros(c2, numel(allCells_array));
for m = 1:c2
for n = 1:numel(allCells_array)
movement = all_comb_of_routes{m} * allCells_array{n};
total=sum((sum(movement > 0, 2)) -1);
total_all(m,n) =total;
end
end
minValue=min(total_all)
[all_comb_of_routes(m) allCells_array(n) combination_array(n) minValue];
toc;
2 Comments
Image Analyst
on 14 Jan 2017
Undefined function or variable 'allcomb'.
Error in test1 (line 15)
a = allcomb(1:z(1),1:z(2),1:z(3),1:z(4),1:z(5),1:z(6));
You forgot to give us allcomb(). Or, if it's in one special toolbox, then you forgot to list what toolbox(es) is/are required to run your code.
Accepted Answer
Niels
on 14 Jan 2017
concerning your problem with the minimum:
you can either use
minValue=min(total_all(:));
% if you want/ need the index:
[minValue,IndexminVal]=min(total_all(:));
or use the min command twice
minValue=min(min(total_all));
the result is the same
0 Comments
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!