mean of all positives in a cell array

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I have a cell array where the cells are something like this: [ 92x1 double] [215x1 double] [127x1 double] [120x1 double] [ 89x1 double] ....and so on(1000 odd cells). I want to find the means of the negative and positive elements in these cells individually. I tried :
if true
% code
end
m = (s{i})<0;
m1 =cellfun(@(x) [mean(mean(x(m,:),2))],s,'un',0)
but when I try the same for all positive elements using n = (s{i})>0; it says index exceeds matrix dimension. Any idea of what I may be doing wrong and how I can fix this or any other suggestions? Thanks!
  1 Comment
Hiskiel Stephanus
Hiskiel Stephanus on 11 Nov 2016
Hi
Please find a solution to your problem in the attached Matlab file. You should of course adjust it accordingly to suit your needs.
Regards Hiskiel

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Accepted Answer

Andrei Bobrov
Andrei Bobrov on 11 Nov 2016
Edited: Andrei Bobrov on 11 Nov 2016
m1 =cellfun(@(x) [mean(x(x<0)),mean(x(x>0))],s,'un',0)
  5 Comments
BoIs
BoIs on 11 Nov 2016
Thankyou both!! that worked!
BoIs
BoIs on 11 Nov 2016
Im new to matlab, just wanted to know how does the ; at the end exactly help with the error? Thanks!

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