How to convert decimal matrix matrix into binary matrix?

hi

I want to convert 3 by 4 decimal matrix into equivalent 3 by 4 binary matrix

e.g

a=[10 9 8 7
    9 7 9 6
    1 2 3 8]

b=[1010 1001 1000 0111
   1001 0111 1001 0110
   0001 0010 0011 1000]

kindly help me I will be highly thankful to you

regards, mudasir

Answer 1

[Guillaume]

Note there's not such thing as

b=[1010 1001 1000 0111
   1001 0111 1001 0110
   0001 0010 0011 1000]

in matlab. Binary matrices don't exist in matlab.

The closest you can get is a cell array of string, which you'll obtain with:

a = [10 9 8 7
      9 7 9 6
      1 2 3 8]
b = reshape(cellstr(dec2bin(a)), size(a))

which produces:

b = 
  3×4 cell array  
    '1010'    '1001'    '1000'    '0111'
    '1001'    '0111'    '1001'    '0110'
    '0001'    '0010'    '0011'    '1000'

[Mudasir Ahmed]

Dear sir,

Thank you so much, it's now working.

sir whats the procedure of returning it back to the original form like

a = [10 9 8 7
      9 7 9 6
      1 2 3 8]

and my second question is if I want to send bit from one set to another set like

'1010' and '1001'

if I cut after 3rd digit in 1010 and replace 4th digit "0" with the 4th digit of 1001 like : ans: (1011)

how i do the above operation.

kindly sir guide me. thanks

[Guillaume]

a = reshape(bin2dec(b), size(b))

to get the original a back.

As far as matlab is concerned, there's nothing binary about b, they're just strings (that happen to contain 0 and 1). You can of course manipulate strings and replace characters:

c = cellfun(@(s) [s(1:3), '1'], b, 'UniformOutput', false);

But if all you want to do is change a bit, then you're better off staying with the original decimal array and use bitset:

bitset(a, 1, 1)  %set bit 1 to 1

Answer 2

[Andriy Kavetsky]

Use dec2base(a,2) command to get string array of binary numbers and str2num(dec2base(a,2)) to convert string into numbers

[Mudasir Ahmed]

Dear sir, it gives the following error

Error using dec2base (line 22) First argument must be an array of integers, 0 <= D <= 2^52.

[Walter Roberson]

a=[10 9 8 7
    9 7 9 6
    1 2 3 8];
dec2base(a)

gives a char array as output.

To convert back you need to use base2dec()

[Mudasir Ahmed]

Dear sir,

I have number a=50 I want to convert it to binary, then I randomly choose the position in a binary string and compliment it Like

a=50

b=dec2bin(a)

b=110010

position=4

b becomes

b=110110

how i do this sir.