# How to convert decimal matrix matrix into binary matrix?

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Mudasir Ahmed on 23 Oct 2016
Commented: Mudasir Ahmed on 25 Oct 2016
hi
I want to convert 3 by 4 decimal matrix into equivalent 3 by 4 binary matrix
e.g
a=[10 9 8 7
9 7 9 6
1 2 3 8]
b=[1010 1001 1000 0111
1001 0111 1001 0110
0001 0010 0011 1000]
kindly help me I will be highly thankful to you
regards, mudasir

Guillaume on 23 Oct 2016
Note there's not such thing as
b=[1010 1001 1000 0111
1001 0111 1001 0110
0001 0010 0011 1000]
in matlab. Binary matrices don't exist in matlab.
The closest you can get is a cell array of string, which you'll obtain with:
a = [10 9 8 7
9 7 9 6
1 2 3 8]
b = reshape(cellstr(dec2bin(a)), size(a))
which produces:
b =
3×4 cell array
'1010' '1001' '1000' '0111'
'1001' '0111' '1001' '0110'
'0001' '0010' '0011' '1000'
##### 2 CommentsShowHide 1 older comment
Guillaume on 23 Oct 2016
a = reshape(bin2dec(b), size(b))
to get the original a back.
As far as matlab is concerned, there's nothing binary about b, they're just strings (that happen to contain 0 and 1). You can of course manipulate strings and replace characters:
c = cellfun(@(s) [s(1:3), '1'], b, 'UniformOutput', false);
But if all you want to do is change a bit, then you're better off staying with the original decimal array and use bitset:
bitset(a, 1, 1) %set bit 1 to 1

Andriy Kavetsky on 23 Oct 2016
Use dec2base(a,2) command to get string array of binary numbers and str2num(dec2base(a,2)) to convert string into numbers
Mudasir Ahmed on 25 Oct 2016
Dear sir,
I have number a=50 I want to convert it to binary, then I randomly choose the position in a binary string and compliment it Like
a=50
b=dec2bin(a)
b=110010
position=4
b becomes
b=110110
how i do this sir.

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