How to convert decimal matrix matrix into binary matrix?

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hi
I want to convert 3 by 4 decimal matrix into equivalent 3 by 4 binary matrix
e.g
a=[10 9 8 7
9 7 9 6
1 2 3 8]
b=[1010 1001 1000 0111
1001 0111 1001 0110
0001 0010 0011 1000]
kindly help me I will be highly thankful to you
regards, mudasir

Accepted Answer

Guillaume
Guillaume on 23 Oct 2016
Note there's not such thing as
b=[1010 1001 1000 0111
1001 0111 1001 0110
0001 0010 0011 1000]
in matlab. Binary matrices don't exist in matlab.
The closest you can get is a cell array of string, which you'll obtain with:
a = [10 9 8 7
9 7 9 6
1 2 3 8]
b = reshape(cellstr(dec2bin(a)), size(a))
which produces:
b =
3×4 cell array
'1010' '1001' '1000' '0111'
'1001' '0111' '1001' '0110'
'0001' '0010' '0011' '1000'
  2 Comments
Guillaume
Guillaume on 23 Oct 2016
a = reshape(bin2dec(b), size(b))
to get the original a back.
As far as matlab is concerned, there's nothing binary about b, they're just strings (that happen to contain 0 and 1). You can of course manipulate strings and replace characters:
c = cellfun(@(s) [s(1:3), '1'], b, 'UniformOutput', false);
But if all you want to do is change a bit, then you're better off staying with the original decimal array and use bitset:
bitset(a, 1, 1) %set bit 1 to 1

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More Answers (1)

Andriy Kavetsky
Andriy Kavetsky on 23 Oct 2016
Use dec2base(a,2) command to get string array of binary numbers and str2num(dec2base(a,2)) to convert string into numbers
  3 Comments
Mudasir Ahmed
Mudasir Ahmed on 25 Oct 2016
Dear sir,
I have number a=50 I want to convert it to binary, then I randomly choose the position in a binary string and compliment it Like
a=50
b=dec2bin(a)
b=110010
position=4
b becomes
b=110110
how i do this sir.

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