How can i shorten the duration this code takes? it takes 0.4 seconds to complete if you insert a longer string. I would prefer not using the for loop but it is still welcome
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Waboraro Olefile
on 1 Sep 2016
Commented: Waboraro Olefile
on 1 Sep 2016
this code scans a string for letters and ignores repeating letters, for example scans 'xyxzyx' and returns 'xyz' as there are only 3 letters present. the goal is to re-write in a way that takes less time to execute. thanks in advance... here is the code
str='shdydjsgdnsladhdksjkhdjksa'
fixed2=str; %ignore the redundancy
A1=fixed2;
for i=1:numel(fixed2)
k=fixed2(i);
A1=regexprep(A1,'(?<=(??@k).*)(??@k)','')
end
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