Attempted to access x(1,2); index out of bounds because size(x)=[105760,1].
5 views (last 30 days)
Show older comments
Manjutha Manavalan
on 31 Aug 2016
Commented: Walter Roberson
on 3 Jul 2019
can you please solve this sir
for i=1:2
for j=2:len-1
x(j,i) = (x(j-1,i) + x(j,i) + x(j+1,i))/3 ;
end
end
i am getting error command Attempted to access x(1,2); index out of bounds because size(x)=[105760,1].
Error in highfrequencynoiseremoval (line 14)
x(j,i) = (x(j-1,i) + x(j,i) + x(j+1,i))/3 ;
0 Comments
Accepted Answer
Azzi Abdelmalek
on 31 Aug 2016
From the error message, it appears that your variable x is a a column vector 105760x1 . In your code you are trying to access x(1,2) which should be in the second column that doesn't exist
3 Comments
shivam verma
on 3 Jul 2019
how you solve this problem can u tll me please. i m a beginner in the imag processing ..
Walter Roberson
on 3 Jul 2019
The original poster of the question looks to have created x as a column vector somehow. That could have occurred if they had used (:) or reshape() to force it to be a column vector. It could also have occurred if they were not careful in how they deleted some data from the array. For example if they used
x(1:5) = [];
instead of
x(1:5,:) = [];
More Answers (0)
See Also
Categories
Find more on Multidimensional Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!