# Replacing NaN with its succeeding values

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Sowmya MR on 2 Aug 2016
Answered: Andrei Bobrov on 2 Aug 2016
I have an array which should replace the NaN with its succeeding value. For example:
A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1]
then output should be
B=[1 1 1 1 0 0 0 0 1 1 1].

Brendan Hamm on 2 Aug 2016
This is simply a 1-dimensional interpolation using the next method with extrapolation:
A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1]
x = 1:length(A); % Create a vector of indices
idx = ~isnan(A); % Find the locations of valid data
% Use the good data to interpolate on all the locations in x.
B = interp1(x(idx),A(idx),x,'next','extrap')
Andrei Bobrov on 2 Aug 2016
+1

Andrei Bobrov on 2 Aug 2016
A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1];
z = flip(A(:));
x = ~isnan(z);
z = z(x);
B = flip(z(cumsum(x)))';

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