How to concatenate 3D cells arrays

Here I am posting my question graphically to illustrate better my question.

I have 2 3D cell array (A, B) with the same cell sizes and different lengths. I want to Concatenate A and B in order to get C which has same cell size but longer length.

[per isakson]

That's a nice presentation of the problem! Wait a minute: "I want to Concatenate A and B" &nbsp Based on your last question, I first thought that you want to concatenate the contents of the cells of the cell arrays, A and B.

Did you try to implement a code based on loops?

[Mori]

No, I dont no how to do it

[Mori]

I have these 3 arrays which each has 11*1 cell and each includes 1*61 cells and each cell has 2252 double.

What I want at the end is a array with 11*1 cell which each of them includes 1*61 cell and each of them now includes 5000 double.

I hope it is clear.

[per isakson]

This description is not consistent with your original question. The cell arrays you describe here are not 3D. And which numbers sum up to 5000? Not 2*2252 anyhow.

By the way, see The XY Problem

[Walter Roberson]

You start with 3 arrays with 11 cells each with 61 cells each with 2252 doubles, which is 1511092 doubles per array, so 4533276 total doubles.

You want to end with 1 array with 11 cells each with 61 cells each with 5000 doubles per array, so 3355000 total doubles.

Where should the (4533276 - 3355000) = 1178276 extra doubles go?

[Mori]

3 arrays with 11 cells each with 61 cells, array A with 2252, B with 700, C with 1000 doubles.

I want an array with 11 cells, each 61 cell each with (2252+700+1000) doubles. first 11 cells is in Y direction, next 61 cells are in X direction and doubles are in Z direction.

*Yes, you right I noticed my figure is not illustrate my problem. Here is the update of the figure. Sorry about that.

[Mori]

Indeed keeping the cell array format and line up the doubles at each cell

Answer 1

[per isakson]

Try

>> R = cssm()
R = 
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
    {61x1 cell}
>> R{1}{1}
ans =
  Columns 1 through 14
     1     2     3     4     5     6     7     8     9     1     2     3     4     5
  Columns 15 through 18
     6     1     2     3

>> R{11}{61}
ans =
  Columns 1 through 14
     1     2     3     4     5     6     7     8     9     1     2     3     4     5
  Columns 15 through 18
     6     1     2     3

and

>> tic, R = cssm(); toc
Elapsed time is 0.008893 seconds.

where

function  R = cssm( )
A = (1:9);
A = repmat( {A}, [61,1] );
A = repmat( {A}, [11,1] );

B = (1:6);
B = repmat( {B}, [61,1] );
B = repmat( {B}, [11,1] );

C = (1:3);
C = repmat( {C}, [61,1] );
C = repmat( {C}, [11,1] );
R = cell( 11, 1 );
for jj = 1 : 11
    D = cell( 61, 1 );
    for ii = 1 : 61
        D{ii} =  cat( 2, A{jj}{ii},  B{jj}{ii}, C{jj}{ii} ); 
    end
    R{jj} = D;
end
end

&nbsp

"next 61 cells are in X direction" &nbsp replace 61,1 by 1,61

"doubles are in Z direction" &nbsp I don't understand what you mean.

[Mori]

GREAT! it works, Thank you

Answer 2

[Walter Roberson]

C = cat(3, A, B);

[Mori]

This is not the one I want. let say A{1,1} has and matrix of [100,1] and B{1,1} has a matrix of [20,1] and so on. with CAT i get 2 sheets but what I need all recorded in on sheet at the same index map. For C{1,1} i want a matrix of [120,1]. thank you