What is the problem with this for loop?

deltaK values are should be "zero" for clock time of 0 - 0.999 sec but its giving the values of 0.1.Please help to solve the issue.

function [Out] = LMAImplementation_Motor(In)
persistent eWithNoChange eWithDeltaL eWithDeltaK
e = In(1);
L = In(2);
K = In(3);
Clock = In(4);
clock = int64(Clock)
for clock = 0.000:0.999
    deltaK = 0; deltaL = 0;
    eWithNoChange(end+1) = e;
    sizeofeWithNoChange = size(eWithNoChange);
end
for clock = 1.000:1.999
    deltaL = L*0.1; deltaK = 0;
    eWithDeltaL(end+1) = e;
    sizeofeWithDeltaL = size(eWithDeltaL);
end
for clock = 2.000:2.999
    deltaL = 0; deltaK = K*0.1;
    eWithDeltaK(end+1) = e;
    sizeofeWithDeltaK = size(eWithDeltaK);
end
deltaK
deltaL
Out = [deltaL,deltaK,Clock];
end

I don't understand why the deltaK values is 0.1 even when the clock values in between 0 and 0.999.

Answer 1

[Roger Stafford]

For each of the for-loops ‘clock’ can take only one value. For example, with "for clock = 1.000:1.999", clock can only be 1.000, since the default step size is 1. I think you meant "for = 1.000:0.001:1.999".

[kintali narendra]

In the simulation the step size is 0.0001

 and clock is given to Zero-order hold to match the simulation step size

[Roger Stafford]

OK, then you should have said

for = 1.000:0.0001:1.999

[kintali narendra]

Roger Stafford I made the above modification but there is no improvement. It is still the same

[Roger Stafford]

You are not using 'clock' anywhere in your for-loops. Your 'e' is zero, so you are stretching 'eWithNoChang' out in long vectors of zeros and nothing else is accomplished. You had better stop and rethink what it is you are trying to do.