how to find and replace corresponding matri

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Triveni
Triveni on 19 May 2016
Edited: VBBV on 26 Jul 2023
a1{:}
ans =
73.3333 50.0000
66.6667 50.0000
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
i need to find index for non zero cell array, and convert in into mat.

Answers (3)

Azzi Abdelmalek
Azzi Abdelmalek on 19 May 2016
Edited: Azzi Abdelmalek on 19 May 2016
idx=celfun(@isempty,a1)
a1(idx)=[]
out=cell2mat(a1)

Andrei Bobrov
Andrei Bobrov on 19 May 2016
out = cat(1,a1{:})

Guillaume
Guillaume on 19 May 2016
Edited: VBBV on 26 Jul 2023
idx = find(~cellfun(@isempty, a1)); %index of non empty cell
assert(numel(idx) == 1, 'There are more or less than 1 empty cell')
out = a1{idx}; %get content of cell, which is a matrix in your case

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