how to find and replace corresponding matri

 a1{:}

 ans =

   73.3333   50.0000
   66.6667   50.0000

 ans =

   Empty matrix: 0-by-2

 ans =

   Empty matrix: 0-by-2

 ans =

   Empty matrix: 0-by-2

 ans =

   Empty matrix: 0-by-2

 ans =

   Empty matrix: 0-by-2

i need to find index for non zero cell array, and convert in into mat.

Answer 1

[Azzi Abdelmalek]

idx=celfun(@isempty,a1)
a1(idx)=[]
out=cell2mat(a1)

Answer 2

[Andrei Bobrov]

out = cat(1,a1{:})

Answer 3

[Guillaume]

idx = find(~cellfun(@isempty, a1)); %index of non empty cell
assert(numel(idx) == 1, 'There are more or less than 1 empty cell')
out = a1{idx}; %get content of cell, which is a matrix in your case