How to use imagesc command?
13 views (last 30 days)
Show older comments
Hello.
I am working on a program through which i want to show my power through imagesc command but i don't know how to use imagesc command.This is the programme i am working on and i want to plot the power through imagesc. Help me.
clc; clear;
[hdf,record]=edfread('Vikram-Maze_with-16.12.15.11.50.57.edf');
d=record(3:16,:);
r=d';
c=record';
mrkrs=record(36,:);
m=mrkrs';
n_start=find(m==5);
c_start=find(m==6)-1000;
c_ends=find(m==7);
n_ends=find(m==8);
n1=r(n_start:n_ends,:);
[b,a]=butter(4,[4 12]/64);
d_theta=filter(b,a,r);
power=100*(norm(d_theta(:,1)).^2)/(length(d_theta));
After this i want imagesc graph thorugh which power is to be shown in graph limited in x and y axis. help me ASAP.
0 Comments
Answers (1)
Walter Roberson
on 4 Apr 2016
norm(d_theta(:,1)) is going to be a scalar, so you are calculating power as a scalar.
It looks to me as if d_theta might have 14 columns, so you could potentially create one power per column, but that would only get you a 1 x 14 vector, which does not seem worth using imagesc() for that. But if you want...
d_power = 100 * sum(d_theta.^2) / size(d_theta,1);
imagesc(d_power)
5 Comments
Walter Roberson
on 5 Apr 2016
Which of the "this" shows a black figure?
You might need
pcolor(t, f, 10*log10(p), 'edgecolor', 'none')
See Also
Categories
Find more on Line Plots in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
