Opposite to horzcat?

How do I subtract a part of a string? i.e the opposite functionality of horzcat. Say that I have a string = 'textstring' and I want to subtract string so that I get string2 = 'text'.

[Stephen23]

Keep in mind that there is no such thing as the opposite of concatenation given just one string as an input, because by concatenating you lose information (i.e. the lengths of the parts). The only way to truly perform the opposite operation to concatenation requires that you store the part lengths as well as the concatenated string.

Answer 1

[Guillaume]

Note that if what you want to do is just separate a filename into its different components, you can use fileparts:

[~, name, extension] = fileparts('kalle.mat')

Answer 2

[Walter Roberson]

Strings are row vector of char, so index the vectors.

string2 = string(1:4);

[nilsotto]

Ok thanks, but what if I only know how many characters from the end that I want to remove? For instance if I have a string = 'kalle.mat' and I want to keep 'kalle' without knowing the length of if.

[Torsten]

string2 = string(1:end-characters_to_be_removed_from_the_end);

Best wishes

Torsten.

[nilsotto]

Many thanks Torsten!

Answer 3

[Torsten]

string2 = string(1:4);

Best wishes

Torsten.