need help with fibo

good afternoon- im noob for this however
I make this code for fibonacci but I dont know how make the code ask for put in two numbers and make this condition while abs(x(k) / x(k-1) –x(k-1)/ x(k-2)) > 0.001
N=input('escoge un numero\n');
fib=zeros(1,N);
fib(1)=1;
fib(2)=1;
k=3;
while k <= N
fib(k)=fib(k-2)+fib(k-1);
k=k+1;
end
fprintf('The Fibonacci sequence to %d terms is\n',N);
fprintf('%g ',fib);
fprintf('\n');

Answers (1)

To ask the user for two numbers, try this snippet:
% Ask user for two floating point numbers.
defaultValue = {'45.67', '78.91'};
titleBar = 'Enter a value';
userPrompt = {'Enter floating point number 1 : ', 'Enter floating point number 2: '};
caUserInput = inputdlg(userPrompt, titleBar, 1, defaultValue);
if isempty(caUserInput),return,end; % Bail out if they clicked Cancel.
% Convert to floating point from string.
usersValue1 = str2double(caUserInput{1})
usersValue2 = str2double(caUserInput{2})
% Check for a valid number.
if isnan(usersValue1)
% They didn't enter a number.
% They clicked Cancel, or entered a character, symbols, or something else not allowed.
% Convert the default from a string and stick that into usersValue1.
usersValue1 = str2double(defaultValue{1});
message = sprintf('I said it had to be a number.\nI will use %.2f and continue.', usersValue1);
uiwait(warndlg(message));
end
% Do the same for usersValue2

2 Comments

thanks can you help me with this to apply in the code while abs(x(k) / x(k-1) –x(k-1)/ x(k-2)) > 0.001
Well, the 0.001 could be one number, but what other number do you want the user to enter?

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on 28 Feb 2016

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on 28 Feb 2016

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