Replacing string by start of this string

Hello All,

would you be so kind, could you advise me, how can i create condition with 'if', when i need replace all columns start with 'something-some string' by other string. For example, I have CPU type:'AMD Opteron 852 Single Core' and I need to replace it by only 'AMD Opteron'....:) Thank you for your help in advance...:)

Answer 1

[per isakson]

Hint:

cac = {'AMD','INTEL','ZILOG'
       'ZILOG','AMD','INTEL' };
cac = regexprep( cac, '^Z.+$', 'Z80' )

outputs

cac = 
    'AMD'    'INTEL'    'Z80'  
    'Z80'    'AMD'      'INTEL'

All strings starting with "Z" are replaced by "Z80"

[Radoslav Vandzura]

But, how can i use it in a cycle for...when i need examine all rows?

[per isakson]

??? regexprep handles all rows in one operation. I showed that with two rows.

[Radoslav Vandzura]

yes, but i have more types of CPU type....for example I need replace: 'IBM Power6 Model 520 Dual Core'- IBM Power 'Itanium 2 9010 Single Core'-Itanium 'AMD Opteron 8218 Dual Core'-AMD...

I need examine all rows in that column....

[per isakson]

Can't you add a new line for each

cac = regexprep( cac, '^I.+$', 'Pentium' )
cac = regexprep( cac, '^A.+$', 'Opteron' )

"I need examine all rows in that column...." &nbsp I don't understand

[Radoslav Vandzura]

This is my column of CPU Type (not all) and I need each row replace by the more simple name...So, I need do it with 'for', I think....

[per isakson]

• "start with 'something-some string'" &nbsp Why "start", your column contains the full names - or what did I miss ?
• Where do you have the "more simple name" ?
• Where do you want to put the new column ?
• I need more context to help.

[Radoslav Vandzura]

I resolved it yet by the following way:

for i=1:length(Tcell)

    split_cell = strsplit(Tcell{i,4});
    status = 0;
    switch split_cell{1}
        case 'IBM'
           status = 1; 
           split_cell = 'IBM';
        case 'AMD'
           status = 1;
           split_cell = 'AMD';
        case 'Intel'
           status = 1;
           split_cell = 'Intel';
    end

    if status == 0
       split_cell = 'Iny'; 
    end

    Tcell{i,4} = split_cell;
end

Thank you :) I appreciate your help and time :)