row by row matrix building

1 view (last 30 days)
Colin Edgar
Colin Edgar on 6 Nov 2015
Commented: Colin Edgar on 9 Nov 2015
Quick question here I hope. Am modifying some code, can't see why this won't work:
j=1
while ischar (tline);
%define indexes, below as idx, etc etc
tline = fgetl(fid); %reads the next line in input file
dt = textscan(tline,'%s','delimiter',',');
tm = datenum(dt{1}(didx));
d1 = str2double(dt{1}(1idx));
d2 = str2double(dt{1}(2idx));
d3 = str2double(dt{1}(3idx));
mat(j,:) = [tm d1 d2 d3]; ;
j = j+1;
tline = fgetl(fid);
end;
The stumbling block is the mat(j,:) portion. Error message says 'Subscripted assignment dimension mismatch.' Tried different ways of creating mat[] prior to this loop and in different ways but no luck. Could do a whole different approach, but don't want to build a whole new routine.
  1 Comment
Image Analyst
Image Analyst on 7 Nov 2015
1idx, 2idx, and 3idx are not valid variable names.

Sign in to comment.

Answers (1)

Image Analyst
Image Analyst on 7 Nov 2015
What is the size of mat? Does it have 4 columns? What is the value of tline and j when the error is thrown? Maybe try preallocating mat before the while loop
mat = zeros(1, 4);
  5 Comments
Image Analyst
Image Analyst on 7 Nov 2015
Well you can't assign 4 numbers to an entire row of 7 columns. If you just want the first 4 columns assigned, you can index it like this:
mat(j,1:4) = [tm d1 d2 d3];
The final 3 columns (columns 5, 6, and 7) will be untouched and remain as zero.
Colin Edgar
Colin Edgar on 9 Nov 2015
I realize that. Sorry my example is smaller than my actual testfile. I still haven't solved this but am doing a workaround. Still interested in a solution. Thx

Sign in to comment.

Categories

Find more on Resizing and Reshaping Matrices in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!