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How to efficiently update an image if one matrix element is changed

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I have a matrix in which I change only one element in every iteration of a loop. I want to display that matrix as an image using image or imagesc. What I am doing now is to update the CData property of the image handle so as to refresh the image of the matrix. With several thousands of iterations, it turned out that the bottleneck is the image/imagesc function according to the Profiler. So I thought of changing the color of the tile corresponding to the changed matrix entry. How can I do that? There would be no problem with the colormap since the matrix only contains zeros and ones.
  9 Comments
dpb
dpb on 18 Oct 2015
Ewwww...that's a bummer, indeed! I'd also not thought of HG2 and latest releases in performance...I understand there is, so far at least, a big dropoff there.

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Accepted Answer

Image Analyst
Image Analyst on 18 Oct 2015
Don't use image. Use set(). See this demo:
grayImage = imread('moon.tif');
hImage = imshow(grayImage);
promptMessage = sprintf('Do you want to assign new pixels,\nor Quit?');
titleBarCaption = 'Continue?';
buttonText = questdlg(promptMessage, titleBarCaption, 'Continue', 'Quit', 'Continue');
if strcmpi(buttonText, 'Quit')
return;
end
for k = 1 : 50 : numel(grayImage);
grayImage(k) = 255; % Make this pixel bright white.
set(hImage, 'CData', grayImage);
end
msgbox('Done');
I think it should be fast enough for you.
  2 Comments
Image Analyst
Image Analyst on 19 Oct 2015
What attached code? Performance drop from what? On my system, my code was faster than a greased cheetah on steroids. So fast I couldn't even see it happen in real time - I just saw the final result.

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