Replace a value with matrix n x m

Hii.... I want to ask how to replace a value with a matrix n x m. Ex: a = (perms[2])', if a(1)=1, replace a(1)with [1 1;1 1], if a(1)=2, replace it with [2 2;2 2].
Thank you
Muammar

 Accepted Answer

You cannot replace a scalar element of a numeric matrix with a non-scalar.
What you could do is
a = num2cell((perms[2])');
Then
a{1} = a{1} * ones(2,2);
Notice the curly-bracket indexing rather than round-bracket indexing.

7 Comments

I tried, but i think it changed to string. can we change it back to numeric?
It did not change to string. It changed to cell array. And no, you cannot change it back to numeric array because you have entries of different sizes.
Sorry my mistake, not string but cell array. Ok thank you.. Actually i want to find cross-validation, but i have to change data number randomly, not its values. But thank you very much...
Muammar
If you want to access a random element from a matrix A, then
p = 1 + floor(numel(A) * rand(1,1));
A(p) is then the random element.
If you want to access a random row from a matrix A, then
p = 1 + floor(size(A,1) * rand(1,1));
A(p,:) is then the random row.
Thank you, I will try. I am so sorry if it takes your time.
Your comment about permutations would seem to indicate that you want to get out the matrix
[[1 1;1 1],[2 2;2 2]; [2 2;2 2], [1 1; 1 1]]
which would be
[1 1 2 2; 1 1 2 2; 2 2 1 1; 2 2 1 1]
which would be a 4 x 4 matrix, not a 1 x 2 matrix.
My *guess* is that what you really are looking for is ndgrid:
[P,Q] = ndgrid(numel(data), numel(data));
P = P(:);
Q = Q(:);
Then permutation #K would be
[data(P(K)), data(Q(K))]
so the n x 2 matrix formed by [P,Q] would be pairwise indices in to the data:
PQ = [P,Q];
the K'th row of which would be used to fetch the K'th permutation:
data(PQ(K,:))
I will try this one, actually what i need is similar to your first answer,"a{1} = a{1} * ones(2,2);", but i cant make it a numerical values. But, thank you..

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More Answers (2)

Maybe:
data1 = ones(2);
data2 = magic(2);
D = [data1;data2];
D2 = reshape(flipdim(reshape(D',size(data1,1),size(data1,2),[]),3),size(D))
?

9 Comments

if i have A = [ data1; data2], data1 has 2 x 2 matrix, and also for data2. But when i make permutation it could be A = [data2;data1] so i have to call data2 first.
Thank you
Muammar
Sorry, I do not understand what you are trying to say here. The part that I do understand has no obvious connection to replacing the 1x1 entry at A(1) with the 2x2 entry [1,1;1,1] or [2,2;2,2] that you were asking about ?
Walter, I think he wants the result to be the switch the concatention order of data1,data2, though it's very unclear.
it is like if A =[data1;data2], data1 = [1 1], data2 = [4 4], now i want to change A=[data1 ; data2] to be A=[1 1;4 4], i change to 1 x 1 matrix.
Thank you
Muammar
I am sorry.. Actually i want to make permutation with 2 data, the results could be [data1 data2;data2 data1], when data1 appears i need it to be [1 1;1 1], when data2 it should be [2 2;2 2].. I am so sorry if i make you confuse because i just start using MATLAB.
Thank you
Huh? You didn't change A at all. It's still [data1;data2] which is [1 1;4 4] - no change at all. And what is supposed to be a 1x1 matrix?
A=[1 1;4 4] is not a 1 x 1 matrix: it is a 2 x 2 matrix. The only way to make a 1 x 1 matrix as a result would be to use
A = {[1 1;4 4]};
which would create a 1 x 1 cell array.
All.. I am sorry if its not clear
it should be 2 x 2 matrix

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I agree with the others - unclear. Perhaps you mean this:
m = randi(9, [1 4]) % Sample row vector with random integers
m2 = imresize(m, 2, 'nearest') % Do the replication.
Results:
m =
7 8 2 5
m2 =
7 7 8 8 2 2 5 5
7 7 8 8 2 2 5 5
So maybe you can just simply use imresize to get what you want.

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