The input value can be represented by the values of a curve？

Calculation：z=c.^4+b.^4-c.^2-exp(c+b)-2.*c.*b-b.^2

Here，b=1;

A curve represent the values of c

 The values of c versus time

Thus，the values of z can also be represented by a curve？

program： x=[0 25 50 70 80 100]; y=[0 5 7 9 10 11]; a=polyfit(x,y,3); syms X fy=vpa(poly2sym(a,X),4)

x1=min(x):max(x);

h1=polyval(a,x1);

c=fy;b=1;

z=c.^4+b.^4-c.^2-exp(c+b)-2.*c.*b-b.^2

Where is the curve of c？

Answer 1

[Andrei Bobrov]

x = [0 25 50 70 80 100]; 
y = [0 5 7 9 10 11]; 
a = polyfit(x,y,3); 
c = polyval(a,min(x):max(x));
b = 1;

z = c.^4+b.^4-c.^2-exp(c+b)-2.*c.*b-b.^2;

[jixie zhuangbei]

Thank you！ Have you run the program before ?