problem in ycbcr color space
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Ashmil Mohammed
on 27 Jun 2015
Answered: Walter Roberson
on 29 Jun 2015
I am facing some problems in using the ycbcr color space. For a certain purpose this model is the most suitable. But conversion from RGB to ycbcr yields me some negatives values too... Please help. Why does this happen? Are there any ways to solve this?
1 Comment
Star Strider
on 27 Jun 2015
It will help if you posted (or attached) your code, and attached your image.
Accepted Answer
Walter Roberson
on 29 Jun 2015
My speculation would be that you started with a uint8() image, used double() on that, and asked to use rgb2ycbcr() on the result. That could result in negative values, as the datatype of what you ask to convert (uint8 or double) determines which range of values are expected (0 to 255, or 0.0 to 1.0).
Always remember: the result of applying double() to a uint8 image is not an image! If you want your image represented in double precision then use im2double() not just double()
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More Answers (2)
Image Analyst
on 28 Jun 2015
I'm not that familiar with that particular color space. What conversion are you using? I see from https://en.wikipedia.org/wiki/YCbCr that there is a minus sign in the formulas so perhaps they can go negative. I assume you're using rgb2ycbcr(). What colors are you getting negative values for?
2 Comments
Image Analyst
on 28 Jun 2015
If you answer my questions, maybe I can answer yours . OK, if you won't tell me the colors, then maybe you could upload the image. Uploading your m-file, or at least a snippet, would make me more likely to try it, and sooner, than if I had to write it myself.
Thorsten
on 28 Jun 2015
You have some error in your formula. RGB values in the range 0, 255 or R'G'B' values in the range 0..1 map to non-negative YCbCr values. See https://en.wikipedia.org/wiki/YCbCr
5 Comments
Image Analyst
on 29 Jun 2015
Walter, the answer is 16. Ashmil, it's probably best you switched to HSV color space, though I was wondering what situation you had that made you original think "For a certain purpose this model is the most suitable". I think for most situations that I know of, conversion to HSV is fine. The only time I switch to LAB is if I need to compute a color difference because the Delta E formula in LAB space is much, much simpler than it is in HSV color space.
Walter Roberson
on 29 Jun 2015
16 is the answer to be expected from the description of YCbCr in Wikipedia.
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