I don't understand what is the problem.....i tried it, but get an error. So plz help me to solve the problem...

1 view (last 30 days)
"Write a function called integerize that takes as its input a matrix A of non-negative integers of type double, and returns the name of the “smallest” unsigned integer class to which A can be accurately converted. If no such class exists, the string 'NONE' is returned. For example, if the largest integer A is 14, then the function would return 'uint8', but if the largest integer in A is 1e20, then the function would return 'NONE'."

Answers (5)

Walter Roberson
Walter Roberson on 30 May 2015
hint: log2()

Image Analyst
Image Analyst on 30 May 2015
Hint: see functions intmax() and max()
mavValue = max(A(:))
if maxValue < intmax('uint8')
and so on...
  3 Comments
Muhammad Usman Saleem
Muhammad Usman Saleem on 1 Jun 2015
@image in another approach i use..
function integ=integerize(A)
if int(A) && uint(A)
if max(A)<=intmax('uint16')
integ='uint16';
elseif max(A) <= intmax('uint32')
integ='uint32';
elseif max(A) <= intmax('uint64')
integ='uint64';
elseif mod(A,1)=>0
integ='NONE';
end
end
end
but the error remains same as mentioned above..

Sign in to comment.


Mostafa Farhoudi
Mostafa Farhoudi on 15 Jul 2015
Edited: Walter Roberson on 16 Jul 2015
function integ=integerize(A)
integ = 'none';
maxValue=max(A(:));
disp(maxValue);
if maxValue <= intmax('uint8')
integ='uint8';
elseif maxValue<=intmax('uint16')
integ='uint16';
elseif maxValue <= intmax('uint32')
integ='uint32';
elseif maxValue <= intmax('uint64')
integ='uint64';
else
integ='NONE';
end
end

charu sharma
charu sharma on 20 Aug 2015

Pranash Azrot
Pranash Azrot on 25 Aug 2015
yaar mera answer teek see.
function u = integerize(A)
g =max(max(A));
if (g>255 && g<=intmax('uint16'))
u = 'uint16';
elseif (g<0 || g>intmax('uint64'))
u = 'NONE';
elseif (g>intmax('uint16') && g<=intmax('uint32'))
u = 'uint32';
elseif (g>intmax('uint32') && g<=intmax('uint64'))
u = 'uint64';
else
u = 'uint8';
end

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!