Read csv files by regulare expression function

2 views (last 30 days)
Hi,
I have multiple .csv files in the following format from:
TRMM_1998_01_newntcl.csv
TRMM_1998_02_newntcl.csv
.
.
.
TRMM_1998_12_newntcl.csv
TRMM_1999_01_newntcl.csv
.
.
.
TRMM_1999_12_newntcl.csv
I have the following code and I need to modify to read by month (1-12). I appreciate if someone can help me to figure this out and modify the following code.
Thanks in advance.
sad = dir('TRMM_*_newntcl.csv');
cac = regexp( {sad.name}, '1998_[01]\d_[0-3]\_' );
ism = not( cellfun( @isempty, cac ) );
d = sad(ism);
ymdh=cell2mat(textscan([d.name], ...
'TRMM_%4d_%2d_%2d%2d_newntcl.csv', ...
'collectoutput',true));

Accepted Answer

Walter Roberson
Walter Roberson on 7 May 2015
month_to_match = 8; %for example
str_for_month = sprintf('%02d', month_to_match);
regexp_for_month = [ '^TRMM_[12]\d{3}_[01]\d_' str_for_month '_'];
cac = regexp( {sad.name}, regexp_for_month );
  3 Comments
Walter Roberson
Walter Roberson on 8 May 2015
regexp_for_month = [ '^TRMM_[12]\d{3}_' str_for_month '_'];

Sign in to comment.

More Answers (1)

Stephen23
Stephen23 on 7 May 2015
Edited: Stephen23 on 7 May 2015
You could avoid the whole regexp thing entirely by using my FEX submission datenum8601:
>> N = cellfun(@datenum8601, strrep({sad.name},'_','-'));
>> datevec(N)
ans =
1998 1 1 0 0 0
1998 2 1 0 0 0
1998 12 1 0 0 0
1999 1 1 0 0 0
1999 12 1 0 0 0
  1 Comment
Damith
Damith on 7 May 2015
Thanks Stephen.But, I need to somehow use to above approach with regexp function.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!