Can matlab give me difference equation from transfer fucntion
86 views (last 30 days)
Show older comments
Hi My transfer function is H(z)= (1-z(-1)) / (1-3z(-1)+2z(-2))
How can i calculate its difference equation. I have calculated by hand but i want to know the methods of Matlab as well
0 Comments
Accepted Answer
Wayne King
on 12 Nov 2011
I think I'm trying to say that you see it right away if you have the Z-transform. Do you have the System Identification Toolbox? You can do:
M = idpoly([1 -3 2],[1 -1],'NoiseVariance',0)
2 Comments
Ben Le
on 4 Feb 2017
Hi, If I don't have System Identification Toolbox, how can I do it in Matlab? Thanks.
More Answers (3)
Gert Kruger
on 29 Jul 2015
Edited: Gert Kruger
on 29 Jul 2015
syms z;
H = (1-z^-1) / (1-3*z^-1+2*z^-2);
[N, D] = numden(H);
Nc = eval(coeffs(N)); %Get coeffs and evaluatle symbolic variable, i.e. make real matrix
Dc = eval(coeffs(D));
Nc = Nc./(Dc(1)); %Turn into proper polynomial, first coeffs of a is 1
Dc = Dc./(Dc(1));
M = idpoly(Dc, Nc, 'NoiseVariance',0)
0 Comments
Wayne King
on 12 Nov 2011
You have the difference equation:
H(z)= (1-z(-1)) / (1-3z(-1)+2z(-2))
y(n)-3*y(n-1)+2*y(n-2) = x(n)-x(n-1);
zplane([1 -1],[1 -3 2]);
This is not stable, you have a pole outside the unit circle.
See Also
Categories
Find more on Stability Analysis in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!