3 views (last 30 days)

So my plan is the following (create "adaptive" pre/deemp. using Matlab 2015a):

- 1. Read an Audiodata ([y,fs]) and generate white Noise with a certain SNR ([n,fs])
- 2. Generate a Filter H which shapes the PSD(y) similiar to the PSD(n)
- 3. Generate an inverse Filter G=H^(-1) which reverts the effect of H.
- 4. Get the output signal

The code I was thinking to use for this is the following:

[y,fs]=audioread('test.wav');

snr=5;

n=awgn(y,snr,'measured')-y;

[pyy,f]=pwelch(y,[],[],length(y)*2-1,fs);

[pnn,fn]=pwelch(n,[],[],length(y)*2-1,fs);

H=sqrt(snr*pnn./pyy);

G=1./H;

outy=ifft(fft(y).*H.*G);

outn=ifft(fft(n).*G);

out=outy+outn;

[pout,fout]=pwelch(outy,[],[],length(outy)*2-1,fs);

[pnout,fnout]=pwelch(outn,[],[],length(outn)*2-1,fs);

There are two problems when using the code above:

- 1. The pnout should be shaped liked pout (which it isn't).
- 2. The outputsignals (outy,outn) are both complex and therefore it is not possible to play the outputfile.

If I try it another way:

[y,fs]=audioread('test.wav');

snr=5;

n=awgn(y,snr,'measured')-y;

N=length(y);

bin_vals=0:N-1;

fax_Hz= bin_vals*fs/N;

N_2=ceil(N/2);

pyy=(fft(y).*conj(fft(y)));

pnn=(fft(n).*conj(fft(n)));

H=sqrt(snr*pnn./pyy);

G=1./H

outy=ifft(fft(y).*H.*G);

outn=ifft(fft(n).*G);

out=outy+outn;

I don't come across the previous problems but in this case I don't use a real PSD but the squared absolute of the frequencydomain-values. (and as I understand it this would give me the power spectrum and not the power spectral density)

Any ideas why my first way is wrong or how to change my second way to get a real "proper" PSD and not just the PS?

Thanks! Klaus

Youssef Khmou
on 19 Apr 2015

When using the reverse fft function, we take the real part, in one of the equations H.*G is not necessary since G=H.^-1, another method to generate noise is given in the following version, however it still needs scaling operation.

[y,fs]=audioread('test.wav');

snr=5;

sy=std(y);

sn=sy/snr;

n=sn*randn(size(y));

[pyy,f]=pwelch(y,[],[],length(y)*2-1,fs);

[pnn,fn]=pwelch(n,[],[],length(y)*2-1,fs);

H=sqrt(pnn./(pyy*snr));

G=1./H;

outy=(real(ifft(fft(y))));

outn=(real(ifft(fft(n).*G)));

out=outy+outn;

[pout,fout]=pwelch(outy,[],[],length(outy)*2-1,fs);

[pnout,fnout]=pwelch(outn,[],[],length(outn)*2-1,fs);

figure;

plot(fnout,pout,fnout,pnout,'r');

Youssef Khmou
on 19 Apr 2015

I think the first question is not well interpreted, maybe it consists of generating noisy version of y instead of white noise, in this case, the result is sufficiently accurate :

[y,fs]=audioread('test.wav');

snr=5;

n=awgn(y,snr,'measured');

[pyy,f]=pwelch(y,[],[],length(y)*2-1,fs);

[pnn,fn]=pwelch(n,[],[],length(y)*2-1,fs);

H=sqrt(pnn./(pyy*snr));

G=1./H;

outy=real(ifft(fft(y).*H.*G));

outn=real(ifft(fft(n).*G));

out=outy+outn;

[pout,fout]=pwelch(outy,[],[],length(outy)*2-1,fs);

[pnout,fnout]=pwelch(outn,[],[],length(outn)*2-1,fs);

figure;

semilogy(fout,pout,fnout,pnout,'r');grid on;

xlabel('fr [Hz]');

ylabel('magnitude ');

Youssef Khmou
on 19 Apr 2015

from these tests, i think the problem is related to the method used to estimate the psd, especially the overlap issue and number of segments, let us try a last solution using standard psd function instead of pwelch, this requires a scaling of fft, try the following :

N=2000;

%[pyy,f]=pwelch(y,[],[],length(y)*2-1,fs);

[pyy,f]=psd(y,N);

%[pnn,fn]=pwelch(n,[],[],length(y)*2-1,fs);

[pnn,fn]=psd(n,N);

H=sqrt(pnn./(pyy*snr));

G=1./H;

outy=real(ifft(fft(y,N/2+1)));

outn=real(ifft(fft(n,N/2+1).*G));

out=outy+outn;

%[pout,fout]=pwelch(outy,[],[],length(outy)*2-1,fs);

[pout,fout]=psd(outy,N);

%[pnout,fnout]=pwelch(outn,[],[],length(outn)*2-1,fs);

[pnout,fnout]=psd(outn,N);

Youssef Khmou
on 20 Apr 2015

Here is another solution using two sided psd rather than one sided (psd or pwelch) in this case, we use the absolute value of fft :

% data

clear;

fs=1000;

ts=1/fs;

f=fs/4;

t=0:ts:0.1-ts;

y=sin(2*pi*f*t);

% altered part

snr=5;

sy=std(y);

sn=sy/snr;

n=sn*randn(size(y));

pyy=abs(fft(y));

pnn=abs(fft(n));

H=sqrt(pnn./(pyy*snr));

G=1./H;

outy=y;

outn=real(ifft(fft(n,length(y)).*G));

out=outy+outn;

[pout,fout]=psd(outy);

[pnout,fnout]=psd(outn);

figure;

semilogy(fout,pout,fnout,pnout,'r');grid on;

xlabel('fr [Hz]');

ylabel('magnitude ');

Sign in to comment.

Sign in to answer this question.

Opportunities for recent engineering grads.

Apply Today
## 0 Comments

Sign in to comment.