DATA ANALYSIS

Hi,

I have a problem which is outlined below:-

x = 1:5;

y = 1:5;

t = -1:1/2:1;

u = 0:1/2:2;

I then calculate

for i = 1:5

    z = y(:,i) - ( t(:,i) + ( u .* x(:,i) ) )

end

This then yields

z =

    2.0000    1.5000    1.0000    0.5000         0

z =

    2.5000    1.5000    0.5000   -0.5000   -1.5000

z =

    3.0000    1.5000         0   -1.5000   -3.0000

z =

    3.5000    1.5000   -0.5000   -2.5000   -4.5000

z =

    4.0000    1.5000   -1.0000   -3.5000   -6.0000

I would like it to output in the form

z =

Columns 1 through 8

    2.0000    1.5000    1.0000    0.5000         0    2.5000    1.5000    0.5000
Columns 9 through 16

   -0.5000   -1.5000    3.0000    1.5000         0   -1.5000   -3.0000    3.5000
Columns 17 through 24

    1.5000   -0.5000   -2.5000   -4.5000    4.0000    1.5000   -1.0000   -3.5000
Column 25

   -6.0000

Is this possible please?

Any help would be greatly appreciated

Answer 1

[bym]

I suggest going over the getting started documentation and taking a look at this

x = 1:5;
y = 1:5;
t = -1:1/2:1;
u = 0:1/2:2;

y = repmat(y,5,[]);
t = repmat(t,5,[]);

z = y-(t+u'*x);
z = z(:)'