Clear Filters
Clear Filters

Taylor Series Expansions for sin(x)

17 views (last 30 days)
Spaceman
Spaceman on 22 Mar 2024
Commented: Spaceman on 8 Apr 2024
Given: sin(x)=(-1)^i*x^(2*i=1)/(2i+1)!...or... ...
Find: Code that calculates the Taylor series for sin(pi/3) using the equation above
Issue: It just seems like my code isn't approximating right, anything I am overlooking here?
My Solution: I also am unsure of how to compare the CORRECT summation results to realsin which happens to be 0.866
x=pi/3;
sum1=0;
N=10;
for i=0:N
a=(2*i+1);
sum1=(-1).^i.*(x.^(2i+1))./factorial(a);
fprintf('This is the estimate of sin(pi/3): %10e \n',sum1)
% diff=sum1-sin(pi/3);
end
% Could also use the input function to have the user enter a number>10, factorial is accurate up to N<=21
% summation here is always negative every other value?
% realsin=pi/3=0.8660
% Need a way to display how close my estimate was, difference between,
% howclose=diff(sum1, realsin)
% fprintf('Estimate was ... off of actual value: %0.10e', howclose)

Accepted Answer

Voss
Voss on 22 Mar 2024
2i should be 2*i.
And you need to accumulate the sum; as it is now sum1 is only the current term and it's never added to anything.
  11 Comments

Sign in to comment.

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Tags

Products


Release

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!