Unable to comprehend "time" function output

d = caldays(8:10) + hours(1.2345)
d = 1×3 calendarDuration array
8d 1h 14m 4.2s 9d 1h 14m 4.2s 10d 1h 14m 4.2s
t = time(d) % this output
t = 1×3 duration array
01:14:04 01:14:04 01:14:04
Is this output returning the difference between time components of calenderDuration function or only time duration between time values in the array ? can anyone tell more about this output

 Accepted Answer

"Is this output returning the difference between time components of calenderDuration function or only time duration between time values in the array "
Neither, there are absolutely no differences involved.
Exactly as the TIME documentation states, it returns the time component of calendar duration objects.
In pseudo-nomenclature, if you have this CALENDARDURATION array:
99 days 12h 34m 56s789
then TIME returns the time part only (as a DURATION array):
12h 34m 56s789

2 Comments

If differences were involved this would not work:
d = caldays(8) + hours(1.2345)
d = calendarDuration
8d 1h 14m 4.2s
t = time(d)
t = duration
01:14:04
t.Format = "hh:mm:ss.SSS"
t = duration
01:14:04.200
Ok, Thanks for explanation @Stephen23

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Asked:

on 9 Feb 2024

Edited:

on 9 Feb 2024

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