Seeking Help: Deleting Redundancy in a Structure Array

Hello,

I hope this message finds you well. I have a question regarding comparing elements in a structure array in MATLAB. Below is the code snippet I am working with, and I'm looking for guidance on identifying and removing redundancy

clear
clc 

a(1).pos=[1,7,1];
a(2).pos=[1,7,1];
a(3).pos=[6,5,5];
a(4).pos=[1,4,3];
a(5).pos=[2,2,2];

In this example, I want to find and delete redundant elements within the structure array. Specifically, if I know that a(1).pos and a(2).pos have the same elements, I want to retain only one instance.

I am seeking assistance on how to code this efficiently. Any insights or code snippets would be greatly appreciated. Thank you in advance for your help!

[Bruno Luong]

Can we assume

a(i).pos 

are 1 x 3 numercal array or they can be something else more generic?

[Wei Wen]

hi, it is in numerical array.

Here is a sample of the actual value from the main code. I would like to compare the value from the pop.Position. If there is redundancy, i would like to eliminate it. Are there any ways to do that?

There is no redundancy in the figure below.

Answer 1

[Bruno Luong]

a(1).pos=[1,7,1];
a(2).pos=[1,7,1];
a(3).pos=[6,5,5];
a(4).pos=[1,4,3];
a(5).pos=[2,2,2];

P = cat(1, a.pos);
[~, I] = unique(P, 'rows');

a = a(sort(I));
a.pos

ans = 1×3

1 7 1

ans = 1×3

6 5 5

ans = 1×3

1 4 3

ans = 1×3

2 2 2

[Wei Wen]

Thank you !

[Bruno Luong]

@Wei Wen Can you please accept the answer?