how to plot different horizontal lines over each group of bar plot

9 views (last 30 days)

Accepted Answer

Star Strider
Star Strider on 8 Dec 2023
Edited: Star Strider on 8 Dec 2023
Try something like this —
A = (5+rand(10))/6;
figure
hb = bar(A);
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)], [1 1]*0.75, '-k', 'LineWidth',3)
hold off
figure
hb = bar(A);
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)], [1 1]*0.75, '-k', 'LineWidth',3)
hold off
xlim([0.5 2.5])
Make appropriate changes to get the result you want.
EDIT — (8 Dec 2023 at 13:43)
To extend the lines to cover all the bars in each group (rather than stopping at the midpoints), use the normalised ‘Barwidth’ data as well to extend it —
A = (5+rand(10))/6;
figure
hb = bar(A);
BW = hb.BarWidth
BW = 0.8000
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)]+[-0.5 0.5]*BW/numel(hb), [1 1]*0.75, '-k', 'LineWidth',3)
hold off
figure
hb = bar(A);
BW = hb.BarWidth;
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)]+[-0.5 0.5]*BW/numel(hb), [1 1]*0.75, '-k', 'LineWidth',3)
hold off
xlim([0.5 2.5])
.

More Answers (1)

Dyuman Joshi
Dyuman Joshi on 8 Dec 2023
Here's a demo -
%Random data
mat = randi([11 19], 4, 6);
%Bar plot
b = bar(mat);
hold on
%Get the x-coordinates of each group (center of each bar)
%Each column represents the x-coordinates of each bar group
x = vertcat(b.XEndPoints)
x = 6×4
0.6667 1.6667 2.6667 3.6667 0.8000 1.8000 2.8000 3.8000 0.9333 1.9333 2.9333 3.9333 1.0667 2.0667 3.0667 4.0667 1.2000 2.2000 3.2000 4.2000 1.3333 2.3333 3.3333 4.3333
%Get the coordinates of the end points
x = x([1 end],:).'
x = 4×2
0.6667 1.3333 1.6667 2.3333 2.6667 3.3333 3.6667 4.3333
plot(x, [5 5], 'LineWidth', 2.5, 'Color', 'k');
hold off
  2 Comments
priyam kar
priyam kar on 8 Dec 2023
Thank you very much for your help, your solution also works perfectly, however i used the other solution provided by Mr. Star Strider. Thank you once again

Sign in to comment.

Tags

Products


Release

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!