convert a cell (Rx1 cell) to a vector (Rx1 double)

Hi. I want to convert the cell 'rows_check_n' into a vector of type double with the numbers inside the cell.

I tried 'cell2mat' but it is not clear to me why it transforms 270x1 cell into a vector 257x1 double. How can I solve this?

rows_check_n = load("rows_check_n.mat");
rows_check_n = rows_check_n.rows_check_n;   % 270x1 cell
    
rows_check_n_double = cell2mat(rows_check_n);  % 257x1 double

Answer 1

[Walter Roberson]

13 entries in the cell are empty.

rows_check_n = load("rows_check_n.mat");
rows_check_n = rows_check_n.rows_check_n;   % 270x1 cell
disp(find(cellfun(@isempty, rows_check_n)))

    99
   100
   101
   102
   103
   104
   105
   106
   107
   108
   109
   110
   111

Answer 2

[Stephen23]

"but it is not clear to me why it transforms 270x1 cell into a vector 257x1 double"

It is easy to check your data (you have been using MATLAB for over three years now, you can do this too):

S = load("rows_check_n.mat");
C = S.rows_check_n   % 270x1 cell

C = 270×1 cell array
    {[106798]}
    {[106799]}
    {[106800]}
    {[106801]}
    {[106802]}
    {[106803]}
    {[107309]}
    {[107310]}
    {[107311]}
    {[107312]}
    {[107313]}
    {[107314]}
    {[107315]}
    {[107820]}
    {[107821]}
    {[107822]}

X = cellfun(@isscalar,C);
all(X) % are all of them scalar as you believe? (hint: no)

ans = logical
   0

Lets replace the non-scalar elements of C with NaNs, then you get a vector of the same size as C:

V = nan(size(C));
V(X) = [C{X}]

V = 270×1

106798 106799 106800 106801 106802 106803 107309 107310 107311 107312