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How to solve and plot second order differential equation using ode45?

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Hey there
Im trying to solve and plot the following differential equation using ode45
x''=(-2k*x-2c*x'-r*omega*(cos(omega*t)+(r/L)*cos(2*omega*t))*m+x0*M)/M+m
where
M = 22
m = 0.9
k = 25000
c = 2
omega = 860
L = 0.2
r = 0.07
The starting conditions are :
x0=0
x'0=0
I've tried a bunch of different tutorials, but keep getting different error messages.
Any help is greatly appreciated, thank you!
  4 Comments
Dyuman Joshi
Dyuman Joshi on 23 Nov 2023
Is the value of x0 that appears in the ODE the same as the value of x0 that is one of the initial conditions?
Also, you have defined the variable x_speed in the ODE function, but have not used it. Is there any particular use of that variable?
Studentguy
Studentguy on 23 Nov 2023
Ye, x0 is the same, its just part the equation i arrived at during calculations.
No x_speed isnt used anywhere.

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Answers (1)

Fabio Freschi
Fabio Freschi on 23 Nov 2023
Edited: Fabio Freschi on 23 Nov 2023
In your code there is a mistake in the definition of x(1) and x(2)
I have made a few stylistic changes (parameters outside the function, use of implicit function) and the correction of the equations. In addition, I suggest to let ode45 to choose the timestep and keep the t vector provided as output for the plot
% clear variables, close all
x0 = [0 0];
tspan = [0 10];
% params
M = 22;
m = 0.9;
k = 25000;
c = 2;
omega = 860;
l = 0.2;
r = 0.07;
x0_speed = 0;
x0_pos = 0;
% implicit function
% changes here
% | |
% V V
dxdt = @(t,x)[x(2); (-2*k*x(1)-2*c*x(2)-r*omega^2*(cos(omega*t)+(r/l)*cos(2*omega*t))*m+x0_pos*(M-m))/M];
[t,x] = ode45(dxdt,tspan,x0);
figure
plot(t,x)
figure
plot(t,x)
xlim([0 0.5])
  4 Comments
Sam Chak
Sam Chak on 23 Nov 2023
I double-check. The original 2nd-order differential equation in your question
is slightly different from the state equation you defined in your code:
( - 2*k*x(1) - 2*c*x(2) - r*omega^2*( cos(omega*t) + (r/l)*cos(2*omega*t) )*m + x0_pos*(M - m) )/M;
Please clarify!
Fabio Freschi
Fabio Freschi on 23 Nov 2023
This is why I wrote my code according to the orignal equation (as stated in the comment)

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