How would I plot this and then achieve minimum and maximum.

1 view (last 30 days)
This is the equation
My script looks like this and fails
x=0:0.1:15
y=(x)^3/3-11(x)^2/2+24x
plot(x,y)
Not yet got my head around MatlB

Accepted Answer

Les Beckham
Les Beckham on 21 Nov 2023
Edited: Les Beckham on 21 Nov 2023
x = 0:0.1:15;
% y=(x)^3/3-11(x)^2/2+24x << you were missing multiplication operators *
% and the powers need to be .^ (element-wise operator) instead of ^ (matrix
% operator)
y = x.^3 / 3 - 11*x.^2 / 2 + 24*x;
plot(x, y)
grid on
xlabel x
ylabel y
fprintf('min(y) = %f; max(y) = %f\n', min(y), max(y))
min(y) = 0.000000; max(y) = 247.500000
Also, if you are just getting started with Matlab, I would highly recommend that you take a couple of hours to go through the free online tutorial: Matlab Onramp

More Answers (1)

Sam Chak
Sam Chak on 21 Nov 2023
Hi @Tom
The cubic function does not have global extrema, but it does have a local maximum point and a local minimum point. Are you looking to plot something similar to this?
%% Find local max and local min over a certain range
y = @(x) x.^3/3 - 11*x.^2/2 + 24*x;
xlocal = linspace(1, 10, 90001);
ymax = max(y(xlocal))
ymax = 31.5000
idx1 = find(y(xlocal) == ymax);
xmax = xlocal(idx1)
xmax = 3
ymin = min(y(xlocal))
ymin = 10.6667
idx2 = find(y(xlocal) == ymin);
xmin = xlocal(idx2)
xmin = 8
%% Plot function over a predefined range
x = 0:0.1:15;
plot(x, y(x)), grid on, hold on
plot(xmax, ymax, 'o', 'markersize', 12, 'linewidth', 2)
plot(xmin, ymin, 'o', 'markersize', 12, 'linewidth', 2)
xlabel('x'), ylabel('y')
xt = [xmax-1 xmin-1];
yt = [ymax+15 ymin+15];
str = {'local max','local min'};
text(xt, yt, str)
  2 Comments
Dyuman Joshi
Dyuman Joshi on 21 Nov 2023
I'm a curious as to why you chose to use max() and min() instead of islocalmax() and islocalmin().
Sam Chak
Sam Chak on 22 Nov 2023
Sometimes, I'm accustomed to using functions with the same name in other software. It's good that you introduced islocalmax() and islocalmin().

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