How can draw this kind of graph?

how can we draw a velocity profile of the 3rd-order non-linear boundary value problem that converges for different values? give me code for u'''+u*u''+s*[Gr*G+Gm*H-M*u']=0 where s=0.02, Gm=10, Gr=4 and M=0.1 with boundary condition u=1,u'=0.001; G=0.001; H=0.001 when t=0 and u'=0; G-0; H=0 when t= infinity, where H=2 and G=4 within one graph for Different values of Gm

6 Comments

Have a read here and here. It will greatly improve your chances of getting an answer.
You can attempt a first try with the new ChatGPT-powered AI playground if you have trouble figuring out the first steps.
When does H jump from 0.001 to 2?
When does G jump from 0.001 to 4?
If H switches from 0.001 to 2 at t = ∞, does it mean H stays at 0.001 forever?
Use bvp4c or bvp5c to set up the problem.
@gkb, I'm confused.
You only introduced ONE differential equation in the question.
where the parameters other than the state variables u, , , are constants.
Why do F, G, and H magically appear in the context? Can we settle the first and then post another question for the system of differential equations F, G, H?

Sign in to comment.

Answers (1)

Here's your required code
code_gkb_Matlab
%%%%%%%%%%%%%%%
function code_gkb_Matlab
global eps Gr Gm M Pr Jh Sc S0
%eq1
eps=0.001; Gr=0.5; M=0.5;
% eq2
Pr=1.4; Jh=0.3; %eps M
% eq3
Sc=0.7; S0=0.2;
val=[0.1 0.2 0.3 0.4];
for i = 1:1:4;
Gm = val(i);
solinit = bvpinit(linspace(0,6),[0 1 0 1 0 1 0]);
sol= bvp4c(@shootode,@shootbc,solinit);
eta = sol.x;
f = sol.y;
figure (1)
plot(eta,f(2,:));
xlabel( '\eta');
ylabel('\bf f'' (\eta)');
hold on
end
lgd=legend('Gm = 0.1','Gm = 0.2','Gm = 0.3','Gm = 0.4');
end
function dydx = shootode(eta,f);
global eps Gr Gm M Pr Jh Sc S0
dydx = [f(2)
f(3)
-f(1)*f(3)-eps*(Gr*f(4)+Gm*f(6)-M*f(2))
f(5)
-Pr*f(1)*f(5)+Jh*Pr*((1/eps)*f(3)^2+M*f(2)^2)
f(7)
2*Sc*f(2)*f(6)-Sc*f(1)*f(7)-S0*Sc*(-Pr*f(1)*f(5)+Jh*Pr*((1/eps)*f(3)^2+M*f(2)^2))
];
end
function res = shootbc(fa,fb)
global eps
res = [fa(1)-1; fa(2)-eps; fa(4)-eps; fa(6)-eps; fb(2)-0; fb(4)-0; fb(6)-0];
end

1 Comment

Edited to add formatting and to make it run.

Sign in to comment.

Products

Release

R2023b

Asked:

gkb
on 13 Nov 2023

Edited:

DGM
on 20 Nov 2023

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!