question about code error

hi

i made a code to get value about c2(small letter c2).

b1=180; b2=165; c1=115; A1=120; A2=100;
B1=(60-C1);
syms C1 a C2 c2;
equation1 = c1/sind(C1) == 180/sind(B1);
equation2 = 180/sind(B1) == a/sind(120);

% 방정식 풀기
sol = solve([equation1, equation2], [C1, a]);

% 결과 출력
fprintf('Value of C1: %.2f도\n', sol.C1);
fprintf('Value of a: %.2f\n', sol.a);

B2=(80-C2);
equation3 = a/sind(100) == 165/sind(B2);
equation4 = 165/sind(B2) == c2/sind(C2);

% 방정식 풀기
sol2 = solve([equation3, equation4], [C2, c2]);

% 결과 출력
fprintf('Value of C2: %.2f도\n', sol2.C2);
fprintf('Value of c2: %.2f\n', sol2.c2);

The road using the Cosine Law created a way to obtain

error code:(

Error occurred during: fprintf

Cannot be converted from sym to double.

What's wrong?

Answer 1

[Walter Roberson]

equation3 = a/sind(100) == 165/sind(B2);
equation4 = 165/sind(B2) == c2/sind(C2);
% 방정식 풀기
sol2 = solve([equation3, equation4], [C2, c2]);

You have two equations in 3 symbolic variables -- c2, C2, and a . Therefore when you solve for C2 and c2 then at least one of the solutions is almost certain to be in terms of the unresolved variable a -- and therefore the result will be something that cannot be converted to numeric.

Answer 2

[Dyuman Joshi]

Since you are working with sides, assume the symbolic variable "a" to bepositive. And although angles can be negative, for the given case i.e. a triangle, we can assume them to be positive as well.

b1=180; b2=165; c1=115; A1=120; A2=100;

syms C1 a C2 c2 positive
B1=(60-C1);
equation1 = c1/sind(C1) == 180/sind(B1);
equation2 = 180/sind(B1) == a/sind(120);

% 방정식 풀기
sol = solve([equation1, equation2], [C1, a]);

% 결과 출력
fprintf('Value of C1: %.2f도\n', sol.C1);

Value of C1: 22.75도

fprintf('Value of a: %.2f\n', sol.a);

Value of a: 257.54

%% Use the value of a obtained to solve for other variables
%Note that you can directly get C1 and a as the outputs from solve()
%[C1, a] = solve([equation1, equation2], [C1, a]);
a = sol.a;
C1 = sol.C1;

B2=(80-C2);
equation3 = a/sind(100) == 165/sind(B2);
equation4 = 165/sind(B2) == c2/sind(C2);

% 방정식 풀기
sol2 = solve([equation3, equation4], [C2, c2]);

% 결과 출력
fprintf('Value of C2: %.2f도\n', sol2.C2);

Value of C2: 40.88도

fprintf('Value of c2: %.2f\n', sol2.c2);

Value of c2: 171.15