How to find the slope of a tangent on a point on a nonlinear curve?
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I have a set of data points x and y. I am plotting these on a (x,y) graph. The result is a nonlinear curve. On each and every point on the curve, tangents can be drawn and the slopes for every tangent will be different. I want to know, how I can I draw these tangents and find their slope. Please guide. I am new to MATLAB.
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Accepted Answer
John D'Errico
on 15 Apr 2015
Edited: John D'Errico
on 15 Apr 2015
You cannot find a slope until you define a curve. Simple points are not a curve. You have connected the points in your mind, so you "see" a curve. But all you have are points.
So you need to find a function that interpolates the points. A spline will do. Then differentiate the spline to get the slope.
You will probably want to use tools like spline (to fit a spline), fnder (differentiate it), and fnval (evaluate the derivative).
If these points form a completely general multi-valued relationship, such that there are multiple values of y for a given point x, you can still form a spline model, but it will take an extra step or two to do the work. An example of such a curve is a circle, where a direct spline fit using spline will fail.
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John D'Errico
on 10 Nov 2018
I'm a bit perplexed. I already did share the code. I.e., use pchip, then fnder, then fnval. Other tools might apply in the scenario where you don't want to use pchip, or lack the curve fitting toolbox.
More Answers (1)
farzad
on 15 Apr 2015
I think you just can define a straight line between each of the two point and simply find the slope of that line
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