Hi,I need a help to solve this problem.

Determine the counts of leap years in each range of 100 years starting from 2000 and ending at 3000.Concatenate the counts to make a bar graph.

[Walter Roberson]

Please read http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer

[Sam Chak]

Hi @Upendra Sen

Is 2100 a leap year or not?

[Riya]

No

[Upendra Sen]

It's not leapyear

Answer 1

[Riya]

Hello Upendra Sen,

As per my understanding, you want to determine the counts of leap years in each range of 100 years starting from 2000 and ending at 3000 in MATLAB

In this case, you can refer the algorithm given below:

1. Set up a loop to iterate over each range of 100 years starting from ‘start_year’ and ending at ‘end_year’.

2. Initialize a variable ‘leap_year_count’ to 0 for each iteration.

3. Set up a nested loop to iterate over each year within the current 100-year range.

4. Check if the current year (y) is a leap year by evaluating the conditions:

• If y is divisible by 4 and not divisible by 100, or
• If y is divisible by 400.

5. If the conditions are met, increment ‘leap_year_count’ by 1.

6. After the nested loop, append the ‘leap_year_count’ value to the ‘leap_year_counts’ array.

7. Repeat the loop for the next 100-year range.

8. The resulting ‘leap_year_counts’ array will contain the counts of leap years in each range of 100 years.

Please note that this algorithm assumes that the variables ‘start_year’, ‘end_year’, and ‘leap_year_counts’ are defined and initialized appropriately before executing the code.

Here is attached sample code snippet to demonstrate the same:

% Define the starting year and ending year for the range 
start_year = 2000; 
end_year = 3000; 


% Initialize an empty array to store the counts of leap years 
leap_year_counts = []; 
 

% Iterate over each range of 100 years and count the leap years 
for year = start_year:100:end_year 
    leap_year_count = 0; 
    for y = year:(year + 99) 
        if (mod(y, 4) == 0 && mod(y, 100) ~= 0) || (mod(y, 400) == 0) 
            leap_year_count = leap_year_count + 1; 
        end 
    end 
    leap_year_counts = [leap_year_counts, leap_year_count]; 
end 


% Create x-axis labels for the bar graph 
x_labels = cell(1, length(leap_year_counts)); 
for i = 1:length(leap_year_counts) 
    x_labels{i} = [num2str(start_year + (i-1)*100), '-', num2str(start_year + i*100 - 1)]; 
end 


% Create the bar graph 
bar(leap_year_counts) 
xlabel('100-Year Ranges') 
ylabel('Leap Year Counts') 
title('Leap Year Counts in 100-Year Ranges') 
xticklabels(x_labels) 
xtickangle(45) 

Please note that running this MATLAB code will generate a bar graph showing the counts of leap years in each range of 100 years starting from 2000 and ending at 3099. The X axis labels will indicate the corresponding 100-year ranges.

I hope it helps!

[DGM]

Simplify:

% a row vector of years
years = 2000:3000;

% reshape into columns of N years
% obviously the vector length needs to be a multiple of N
N = 100;
years = years(1:floor(numel(years)/N)*N); % trim vector
years = reshape(years,N,[]); % reshape

% determine if each is a leap year
isleapyear = ~mod(years,4) & (mod(years,100) | ~mod(years,400));

% count the instances in each block
numleapyr = sum(isleapyear,1);

% plot (i'm going to be lazy and not format anything)
bar(numleapyr)

[John D'Errico]

@Riya

Please don't do obvious homework questions on Answers, when no effort has been shown. This does not help the student, who learns nothing more than to post all of their homwork problems on the site, hoping they will find someone willing to do their thinking and work for them. Worse that that, it convinces the next student who comes along to do the same.

If you want to help, then find a way to push the student in the right direction. But posting a complete solution does far more harm than good.