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Loop: for i = 1:L ;

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Edfred
Edfred on 3 Jun 2023
Answered: Torsten on 3 Jun 2023
Hey everyone I have a question regarding the loop as mentioned for i=1:L where e.g. L=400. I have some collected data and for example if I have: data(:,i) = data(:,i-1) * p (p is just a constant) do I have to intialize a value for data(:,i-1) and if yes how for example because I always get the error "Index in position 2 is invalid. Array indices must be positive integers or logical values." because i got the task to do it like that and not to use: data(:,i+1) = data(:,i) * p.
I would be very thankful if someone has an answer for this.

Answers (1)

Torsten
Torsten on 3 Jun 2023
because i got the task to do it like that and not to use: data(:,i+1) = data(:,i) * p.
Then use
for i = 2:L

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