How can I get the number of values within a range?

Hi, I am trying to get the number of values within a range, but this range is moving. For example, I have a value a as the center of my range. So I define my range as a+std. So I get how many values are within such a range. Then I move the range by a shift, such as my new range si (a+shift)+std. The next range will be (a+2shift)+std, and so on. What I have in my code is the following:

lo_edge=center_range-std;
hi_edge=center_range+std;

bunchcenter=center_range;
kk=0;

while bunchcenter<colum_of_int(end)
    kk=kk+1
    bunchcenter=center_range+kk*shift;
    number_values= colum_of_int>=lo_edge & column_of_int<=hi_edge;
end

I would be thankful to have some help.

[Luca Ferro]

so what is the question? is your code not working? if so please describe the results you get and the desired result you would want. Also, if you can, share the data as well

[areshamal]

Hi Luca, yes, I forgot to say that I am getting only zeros. I am expecting to have zeros in most of the ranges, in some ranges one element, and in very rare cases 2 or 3 elements.

The value I am using as center_range is 132.74 and shift 265.48. The std is 36.15.

I attach the data I am working with. It is time data given in ns.

Answer 1

[Pramil]

Your code is almost correct. You just need to update the values of lo_edge and hi_edge inside the loop to reflect the new range. Here is the updated code:

lo_edge = center_range - std;
hi_edge = center_range + std;
bunchcenter = center_range;
kk = 0;
while bunchcenter < colum_of_int(end)
    kk = kk + 1
    bunchcenter = center_range + kk * shift;
    lo_edge = bunchcenter - std; % update lo_edge
    hi_edge = bunchcenter + std; % update hi_edge
    number_values = colum_of_int >= lo_edge & colum_of_int <= hi_edge;
    num_values_within_range(kk) = sum(number_values);
end

Hope it helps :)

[Dyuman Joshi]

Note - Do not use the names of inbuilt function as names for variables. It is not a good practice. Either capitalize std or better, rename it completely.