why solve failed? my error or solve error?
1 view (last 30 days)
Show older comments
I used command solve but recently I had a new equation:
f1=cos(x)*(2*x)^(1/2) + sin(x)/(2*x)^(1/2);
I used solve, but the ans was wrong, then I used Newton method an check the answers were ok
ans =
1.8366
ans =
4.8158
used solve:
>> syms x
>> f1=cos(x)*(2*x)^(1/2) + sin(x)/(2*x)^(1/2);
>> sf1=solve(f1,x)
sf1 =
-227.76766260117050148062548433664
the ans obvisuly was wrong
why solve failed? was my method or command solve?
0 Comments
Answers (2)
Jan
on 6 Apr 2015
The result is obviously correct. Simply try it:
x = -227.76766260117050148062548433664
cos(x)*sqrt(2*x) + sin(x)/sqrt(2*x)
The result is -2.6466e-013i, which is correct inside the expected precision.
0 Comments
Star Strider
on 6 Apr 2015
There are infinitely many real and imaginary roots:
figure(1)
ezplot(real(f1), [-100 100]*pi)
hold on
ezplot(imag(f1), [-100 100]*pi)
hold off
0 Comments
See Also
Categories
Find more on Equation Solving in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!