matlab中定义变​量不满足三角函数之间​的关系?。

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netitan senalar
netitan senalar on 29 Mar 2023
Answered: koboner on 29 Mar 2023
例如我输入如下:
clear all
syms a
cos(a)^2 + sin(a)^2
得到的cos(a)^2 + sin(a)^2结果仍然是它本身,不是1.
这个该怎么解决呢

Accepted Answer

koboner
koboner on 29 Mar 2023
syms g real
a=[sin(g) ,0,cos(g)];
a_unit =[ sin(g)/(abs(cos(g))^2 + abs(sin(g))^2)^(1/2), 0, cos(g)/(abs(cos(g))^2 + abs(sin(g))^2)^(1/2)];
simplify(a_unit)

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