# How can I plot graph using external function?

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I am trying to plot this equation.

I have the values of B, omega_d, zeta, N_k and t_j is the multiples of 1.89.

First, I tried make an external function to represent the equation including sigma and deduce a function about t. Then tried to draw a gragh for t in conclution.

But I am struggling with where to define t_j, call the external function, and making a function about t and plotting it. It's the code that I wrote below.(there will be lots of errors but don't know how to fix it..)

Any comment will be helpfull. Please help, thanks!

<plotting>

clc; clear;

t=0:10;

sum=s(t)

figure(1)

fplot(s, [1,10])

<s.m>

function [sum]= s(t)

B_n=-5.36 ;

omega_d= 400;

zeta=29 ;

N_k=10;

% sum=zeros(1,N_k);

for i=1:N_k

t_j= 1.89.*i;

sum= sum+ exp(-(zeta/2).*(t-t_j)).*(-zeta*(sin(omega_d/2.*(t-t_j)))+ omega_d.*cos(omega_d/2*(t-t_j)));

end

sum=B_n/omega_d.*sum;

end

##### 1 Comment

Rik
on 13 Mar 2023

### Accepted Answer

Rik
on 13 Mar 2023

If you have trouble with Matlab basics you may consider doing the Onramp tutorial (which is provided for free by Mathworks).

In this case the first thing to fix is your usage of sum as a variable name. You really should avoid function names when picking a variable name. If you use sum later on, will you remember that you made it a variable instead of the function?

The next thing is to add an initial value to your output, which we will make 0.

Lastly, when using fplot you need to provide a function handle. You called the function directly instead. You also didn't use any of the previously calculated values. Below I show two ways to plot this function, along with the other corrections to your code.

t=0:10;

sum_value=s(t);

figure(1)

subplot(1,2,1)

fplot(@s,[0 10])

subplot(1,2,2)

plot(t,sum_value) % you can increase level of detail with t=linspace(0,10,50);

function sum_value= s(t)

% Write an explanation of this function here, along with example usage.

B_n=-5.36 ;

omega_d= 400;

zeta=29 ;

N_k=10;

sum_value=0;

for i=1:N_k

t_j= 1.89.*i;

sum_value= sum_value+ exp(-(zeta/2).*(t-t_j)).*(-zeta*(sin(omega_d/2.*(t-t_j)))+ omega_d.*cos(omega_d/2*(t-t_j)));

end

sum_value=B_n/omega_d.*sum_value;

end

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