How to find the order of the power of A matrix?
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Muhammad Usman
on 28 Feb 2023
Edited: Dyuman Joshi
on 28 Feb 2023
Hi, I want to calculate the order of the power matrix A. Here order doesn't mean for rows into columns but the power n of the matrix in modulo 2.
For example:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1309590/image.jpeg)
I try to wrote the code, but not getting the desired reults i.e., 3. Here's the code:
A = [1 0 1;1 1 0;1 0 0];
B = A;
i = 0;
for n = 1:5
P = A*B;
if P == eye(3)
i = i+1;
break;
else
if mod(P(:,:),2)==0
B(mod(P(:,:),2)==0) = 0
else
B(mod(P(:,:),2)~=0) = 1
end
P = A*B;
end
i = i+1;
end
disp(i)
Please help me out.
Thanks
0 Comments
Accepted Answer
Dyuman Joshi
on 28 Feb 2023
Edited: Dyuman Joshi
on 28 Feb 2023
Use isequal to compare matrices and you can directly calculate modulo by mod, you don't need to assign the values specifically -
A = [1 0 1;1 1 0;1 0 0];
B = A;
i = 0;
for n = 1:5
if isequal(B, eye(3))
i = i+1;
break;
else
sprintf('multiplication')
B = A*B
sprintf('calculating modulo 2')
B = mod(B,2)
end
i = i+1;
end
disp(i)
2 Comments
Dyuman Joshi
on 28 Feb 2023
Edited: Dyuman Joshi
on 28 Feb 2023
mod of 2 can only have 2 values, if mod of 2 is not equal to 0 then it is equal to 1.
I have edited my answer, so you can take a look at each step for every iteration.
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