How do I repeat the comand for another line

I need to repeat the command for 10 lines so that the array is 10x60001

The code is

dt = dx1./v;

tempo = [0:dt(:,1):(length(road_x1)-1)*dt(:,1)];

"dt" is an 1x10 array with different values on each column

"tempo" is resulting in a 1x60001 array getting only the first value from dt, I need it to get the values from all the colunms resulting in a 10x60001 array, I tryed tempo = 0:dt:(length(road_x1)-1)*dt but it didn't work either.

sorry if i wasn't clear, my english is a bit rusty.

Answer 1

[KSSV]

dt = dx1./v;  % let dt be 10x1 array 
m = length(dt) ; 
n = 60001 ;
temp0 = zeros(m,n) ; 
for i = 1:n
    tempo(:,i) = 0:dt(i):(length(road_x1)-1)*dt(i) ;  % If this results into 60001
end

In the above the RHS step should result into 1x60001 array. IF not

dt = dx1./v;  % let dt be 10x1 array 
m = length(dt) ; 
n = 60001 ;
temp0 = cell(m,1) ; 
for i = 1:n
    tempo{i} = 0:dt(i):(length(road_x1)-1)*dt(i) ;  
end

If your target is to get only 10x60001 array.

dt = dx1./v;  % let dt be 10x1 array 
m = length(dt) ; 
n = 60001 ;
temp0 = zeros(m,n) ; 
for i = 1:n
    tempo(:,i) = linspace(0,(length(road_x1)-1),n) ;  % This results into 60001
end

[Brenno Selli]

not working yet...

[Brenno Selli]

I tested changing some of the values, I transposed "dt" and now everything seems to work very well and acurated, the biggest problem now is that the 60001 values ​​are appearing in the same cell, the ideal would be to arrange them along the lines of the columns in which they are allocated

[KSSV]

I have given three options.....use the first option or second option.

[Brenno Selli]

Ita working as It should now, thank you very much my dear, it's almost 2AM here in Brazil and your help was generous and kind.

[Image Analyst]

If this Answer solves your original question, then could you please click the "Accept this answer" link to award the answerer with "reputation points" for their efforts in helping you? They'd appreciate it. Thanks in advance. 🙂 Note: you can only accept one answer (so pick the best one) but you can click the "Vote" icon for as many Answers as you want. Voting for an answer will also award reputation points.

Answer 2

[Brenno Selli]

Trying again to code it to another sample, it's resultin in a error

Index exceeds the number of array elements. Index must not exceed 10.

Error in ESTATISTICAS_DESCRITIVAS (line 51)

tempo(:,j) = 0:dt(j):(length(road_x1)-1)*dt(j) ;

the code that I'm using right now is

dt = transpose(dx1./v); %making it a 10x1 array

m = length(dt);

n = length(verticalperf1); %verticalperf1 is na vector 1x60001, I used this vector just because sometimes the length may change and it makes the code run by the size of the verticalperf1

temp0 = zeros(m,n) ;

for j = 1:n

tempo(:,j) = 0:dt(j):(length(road_x1)-1)*dt(j) ;

end

the code results in a array (60001x10) called "tempo", its completely okay, the vallues are good and acurate, it works but the error is not allowing me to proceed, theres any way that I can solve it or just skip this error??