Efficient code for multiple string replace
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Hello,
I am attempting to replace substrings and evaluate equations for a large number of lines. The following code works for what I want:
% Define sets:
sec = ["T", "N"]; co = ["H","F"];
nco = numel(co); nsec = numel(sec);
for cc = 1:numel(co);
for ss = 1:numel(sec);
eval(replace(['tau_payr_#S_#C_bar = 1; '],["#S","#C"], [sec(ss),co(cc)]));
eval(replace(['tau_pinv_#S_#C_bar = 2; '],["#S","#C"], [sec(ss),co(cc)]));
eval(replace(['tau_payr_#S_#C = tau_payr_#S_#C_bar; '],["#S","#C"], [sec(ss),co(cc)]));
eval(replace(['tau_pinv_#S_#C = tau_pinv_#S_#C_bar; '],["#S","#C"], [sec(ss),co(cc)]));
end;
end;
I am wondering whether there's a better way to write this, where I don't have to write eval and replace at each line.
Thanks,
Accepted Answer
More Answers (1)
Walter Roberson
on 2 Feb 2023
0 votes
If you are going to write something like that, then you should write it in the clearest way you can come up with, because you are going to end up spending a lot of time staring at the code when it fails to work the way you expect.
Please read http://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval for information about why we strongly recommend against creating variable names dynamically.
1 Comment
Abeer Reza
on 2 Feb 2023
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