cannot find existing number
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Luis Eduardo Cofré Lizama
on 8 Jan 2023
Commented: Star Strider
on 8 Jan 2023
I have the following data where fs =100;
tstamp =(1/fs:1/fs:12000*(1/fs))
Then when looking for the value 117 (find(tstamp == 117)), the results is [], however, the value does exist though with a trail of zeros (117.0000), is that the prob? how to solve?
Please help with this very likely simple prob.
cheers
Eduardo
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Accepted Answer
Star Strider
on 8 Jan 2023
Actually, I can’t reproduce that exact problem, since it works correctly here —
format long
fs =100;
tstamp =(1/fs:1/fs:12000*(1/fs))
v = find(tstamp == 117)
D = v - 11700
I was hoping to be able to demonstrate floating-point approximation error.
Oh well ...
.
3 Comments
Walter Roberson
on 8 Jan 2023
There are various fairly obscure ways in which the floating point round-off algorithm can end up being changed. That does not happen often, but it can happen.
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